[Lesson 3][Time Complexity] FrogJmp

 

app.codility.com/programmers/lessons/3-time_complexity/frog_jmp/

FrogJmp coding task - Learn to Code - Codility

# X -> Y 도달하기 위해 필요한 점프 수

def solution(X, Y, D):
    if (Y - X) % D == 0:
        return (Y - X) // D
    else:
        return (Y - X) // D + 1


print(solution(10, 85, 30))  # 3